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0=-0.1x^2+143x-2850
We move all terms to the left:
0-(-0.1x^2+143x-2850)=0
We add all the numbers together, and all the variables
-(-0.1x^2+143x-2850)=0
We get rid of parentheses
0.1x^2-143x+2850=0
a = 0.1; b = -143; c = +2850;
Δ = b2-4ac
Δ = -1432-4·0.1·2850
Δ = 19309
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-143)-\sqrt{19309}}{2*0.1}=\frac{143-\sqrt{19309}}{0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-143)+\sqrt{19309}}{2*0.1}=\frac{143+\sqrt{19309}}{0.2} $
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